Usuario:ReynaNesbit5549

I don't believe that the answer is ln(x)x^(ln(x)-2), since the power rule doesn't apply when you have the variable in the exponent. Do the following instead:y x^ln(x)

Taking the natural log of both sides:ln(y)ln(x) * ln(x)ln(y) ln(x)^2

Take the derivative of both sides, using the chain rule:1/y * y' 2 ln(x) / xy' 2 ln(x)/ x * y

Finally, substitute in the first equation, y x^ln(x):y' 2 ln(x) / x * x^ln(x)y'2 ln(x) * x ^ (ln(x) - 1)

Sorry if everything is formatted really badly, this is my first post on answers.com.

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