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		<title>ReynaNesbit5549: Página creada con «I don't believe that the answer is ln(x)x^(ln(x)-2), since the power rule doesn't apply when you have the variable in the exponent. Do the following instead:y x^ln(x)&lt;br&gt;&lt;b...»</title>
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				<updated>2025-06-05T13:12:09Z</updated>
		
		<summary type="html">&lt;p&gt;Página creada con «I don&amp;#039;t believe that the answer is ln(x)x^(ln(x)-2), since the power rule doesn&amp;#039;t apply when you have the variable in the exponent. Do the following instead:y x^ln(x)&amp;lt;br&amp;gt;&amp;lt;b...»&lt;/p&gt;
&lt;p&gt;&lt;b&gt;Página nueva&lt;/b&gt;&lt;/p&gt;&lt;div&gt;I don't believe that the answer is ln(x)x^(ln(x)-2), since the power rule doesn't apply when you have the variable in the exponent. Do the following instead:y x^ln(x)&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;Taking the natural log of both sides:ln(y)ln(x) * ln(x)ln(y) ln(x)^2&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;Take the derivative of both sides, using the chain rule:1/y * y' 2 ln(x) / xy' 2 ln(x)/ x * y&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;Finally, substitute in the first equation, y x^ln(x):y' 2 ln(x) / x * x^ln(x)y'2 ln(x) * x ^ (ln(x) - 1)&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;Sorry if everything is formatted really badly, this is my first post on answers.com.&amp;lt;br&amp;gt;&amp;lt;br&amp;gt;my web page [https://88888clb.com sex người lớn]&lt;/div&gt;</summary>
		<author><name>ReynaNesbit5549</name></author>	</entry>

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